Angles of Polygons

Sum of Angles in a Triangle

The sum of angles in a triangle is 180º.

You can refer to http://www.walter-fendt.de/m11e/anglesum.htm for a graphical proof based on the pairs of angles.

For the sum of angles of other polygons we can either divide the polygons into triangles or use a formula.

Dividing polygons into triangles

For the other polygons, we can figure out the sum of angles by dividing the polygons into triangles. Any polygon can be separated into triangles by drawing all the diagonals that can be drawn from one single vertex.

In the quadrilateral shown below, we can draw only one diagonal from vertex A to vertex B. So, a quadrilateral can be separated into two triangles.

The sum of angles in a triangle is 180º. Since a quadrilateral is made up of two triangles the sum of its angles would be 180º × 2 = 360º

The sum of angles in a quadrilateral is 360º

Formula for the sum of interior angles

We can also use a formula to find the sum of the interior angles of any polygon.

If n is the number of sides of the polygon then,

sum of angles = (n - 2)180° 

Example:

Find the sum of the interior angles of a hexagon (6-sided)

Solution:

Step 1: Write down the formula (n - 2)180° 

Step 2: Plug in the values           (6 - 2)180° = (4)180° = 720°

Answer: The sum of the interior angles of a hexagon (6-sided) is 720°.

The following video shows a problem involving the sum of interior angles of a polygon.

Formula for the sum of exterior angles

The sum of exterior angles of any polygon is 360º.

The following video shows a problem involving the sum of exterior angles of a polygon.

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