# Logarithmic Functions

In these lessons, we will look at how to evaluate simple logarithmic functions and solve for x in logarithmic functions.

Related Topics:
More Logarithms and Algebra Lessons

What are Logarithmic Functions?
We can think of logarithmic functions as the inverse of exponents.
y = logbx ⇔ by = x

### How to solve for x in Logarithmic Equations?

Equations of the form x = loga y can be solved (for any of the three variables y, a or x) by first writing them in exponent form. We must be careful to check the answer(s) to see whether the logarithm is defined.

Take note of the following:

• Logarithms of a number to the base of the same number is 1, i.e. loga a = 1
• Logarithms of 1 to any base is 0, i.e. loga 1 = 0
• Loga 0 is undefined
• Logarithms of negative numbers are undefined.
• The base of logarithms cannot be negative or 1.

Example:

Calculate the value of each of the following:
a) 1og 2 64
b) log 9 3
c) log 4 1
d) log 6 6
e) log 8 0.25
f) log 3–9

Solution:

a) Let x = log 2 64
2x = 64
x = 6

b) Let x = log 9 3
9x = 3
x =

c) Let x = log 4 1
4x = 1
x = 0

d) Let x = log 6 6
6x = 6
x = 1

e) Let x = log 8 0.25
8x = 0.25

f) Let x = log 3– 9
3x = – 9

Since it is not possible for 3x to be negative, log 3–9 is undefined.

Example

Solve logx 4 = 2

Solution:

logx 4 = 2
x2 = 4
x = 2 or –2

Since x is the base, x > 0 and x ≠ 1; so x = –2 is rejected and the only solution is x = 2

Example:

Solve log 3 x = 2

Solution:

log 3 x = 2
32 = x
x = 9

Example:

Solve log x (4x – 3) = 2

Solution:

log x (4x – 3) = 2
x2 = 4x – 3
x2 – 4x + 3 = 0
(x -1)(x – 3) = 0
So, x = 1 or 3

For the logarithm to be defined, the only solution is 3.

How to solve a logarithmic equation using properties of logarithms?
Just as we can use logarithms to access exponents in exponential equations, we can use exponentiation to access the insides of a logarithm. Solving logarithmic equations often involves exponentiating logarithms in order to get rid of the log and access its insides. Sometimes we can use the product rule, the quotient rule, or the power rule of logarithms to help us with solving logarithmic equations.

This video shows how solve a logarithmic equation using properties of logarithms and some other algebra techniques.
Example: Solve 2log3x - log3(x + 6) = 1 How to solve a Logarithmic Equation with Multiple Logs?
When given a problem on solving a logarithmic equation with multiple logs, students should understand how to condense logarithms. By condensing the logarithms, we can create an equation with only one log, and can use methods of exponentiation for solving a logarithmic equation with multiple logs. This requires knowledge of the product, quotient and power rules of logarithms.
Example: Solve log7(x + 4) - log7(x - 4) = log7(5) Techniques for Solving Logarithmic Equations
Examples: Solve and identify any extraneous solutions
a) log3(x + 1) = 2
b) log5(3x - 8) = 2
c) log(x + 2) + log(x -1) = 1
d) log x4 - log 3 = log(3x2) More examples on solving logarithmic equations
Examples:
log2x + log2(x - 3) = 2
log(5x - 1) = 2 + log(x - 2)
ln x = 1/2 ln(2x + 5/2) + 1/2 ln 2

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