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Geometry word problems involves geometric figures and angles described in words. You would need to be familiar with the formulas in geometry.

Making a sketch of the geometric figure is often helpful.

You can see how it is done in the following examples:

Problems involving Perimeter

Problems involving Area

Problems involving Angles

There is also an example of a geometry word problem that uses similar triangles.

Related Topics:

More Algebra Word Problems

Example 1:

A triangle has a perimeter of 50. If 2 of its sides are equal and the third side is 5 more than the equal sides, what is the length of the third side?

Solution:

Step 1: Assign variables:

Let

x= length of the equal side

Sketch the figure

Step 2: Write out the formula for perimeter of triangle.

P=sum of the three sides

Step 3: Plug in the values from the question and from the sketch.

50 =

x + x + x+ 5Combine like terms

50 = 3x+ 5Isolate variable

x3

x= 50 – 5

3x= 45

x=15Be careful! The question requires the length of the third side.

The length of third side = 15 + 5 =20

Answer: The length of third side is 20

Example 2:

Writing an equation and finding the dimensions of a rectangle
knowing the perimeter and some information about the about the
length and width.

The width of a rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions.

Example 1:

A rectangle is 4 times as long as it is wide. If the length is increased by 4 inches and the width is decreased by 1 inch, the area will be 60 square inches. What were the dimensions of the original rectangle?

Solution:

Step 1: Assign variables:

Let

x= original width of rectangle

Sketch the figure

Step 2: Write out the formula for area of rectangle.

A =

lw

Step 3: Plug in the values from the question and from the sketch.

60 = (4

x+ 4)(x–1)Use distributive property to remove brackets

60 = 4x^{2}– 4x+ 4x– 4Put in Quadratic Form

4x^{2}– 4 – 60 = 0

4x^{2}– 64 = 0This quadratic can be rewritten as a difference of two squares

(2x)^{2}– (8)^{2}= 0Factorize difference of two squares

(2x)^{2}– (8)^{2}= 0

(2x– 8)(2x+ 8) = 0We get two values for

x.

Since

xis a dimension, it would be positive. So, we takex= 4The question requires the dimensions of the original rectangle.

The width of the original rectangle is 4.

The length is 4 times the width = 4 × 4 = 16

Answer: The dimensions of the original rectangle are 4 and 16.

Example 2:

This is a geometry word problem that we can solve by writing an
equation and factoring. The height of a triangle is 4 inches more
than twice the length of the base. The area of the triangle is 35
square inches. Find the height of the triangle.

Example 1:

In a quadrilateral two angles are equal. The third angle is equal to the sum of the two equal angles. The fourth angle is 60° less than twice the sum of the other three angles. Find the measures of the angles in the quadrilateral.

Solution:

Step 1: Assign variables:

Let

x= size of one of the two equal angles

Sketch the figure

Step 2: Write down the sum of angles in quadrilateral.

The sum of angles in a quadrilateral is 360°

Step 3: Plug in the values from the question and from the sketch.

360 =

x + x +(x+x) + 2(x + x + x + x) – 60Combine like terms

360 = 4x+ 2(4x) – 60

360 = 4x+ 8x– 60

360 = 12x– 60Isolate variable

x12

x= 420

x= 35The question requires the values of all the angles.

Substituting

xfor 35, you will get: 35, 35, 70, 220

Answer: The values of
the angles are 35°, 35°, 70° and 220°

Example 2:

The sum of the supplement and the complement of an angle is 130 degrees. Find the measure of the angle.

The following video shows an example of how to use similar
triangles to solve a geometry word problem.

Raul is 6 ft tall and he notices that he casts a shadow that's 5
ft long. He then measures that the shadow cast by his school
building is 30 ft long. How tall is the building?

This video illustrates how to find how to use the properties of similar triangles to determine the height of a tree.