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In these lessons, we will learn

- how to draw probability tree diagrams for independent events (with replacement)
- how to draw probability tree diagrams for dependent events (without replacement)

Related Topics:

More Probability Lessons

We can construct a probability tree diagram to help us solve some probability problems.

A **probability tree diagram**
shows all the possible events. The first event is represented by a
dot. From the dot, branches are drawn to represent all possible
outcomes of the event. The probability of each outcome is written
on its branch.

* Example: *

A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.

a) Construct a probability tree of the problem.

b) Calculate the probability that Paul picks:

i) two black balls

ii) a black ball in his second draw

* Solution: *

a)

Check that the probabilities in the last column add up to 1.

b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.

ii) There are two outcomes where the second ball can be black.

Either (B, B) or (W, B)

From the probability tree diagram, we get:

P(second ball black)

= P(B, B) or P(W, B)

= P(B, B) + P(W, B)

* Example: *

Bag A contains 10 marbles of which 2 are red and 8 are black.
Bag B contains 12 marbles of which 4 are red and 8 are black. A
ball is drawn at random from each bag.

a) Draw a probability tree diagram to show all the outcomes the
experiment.

b) Find the probability that:

(i) both are red.

(ii) both are black.

(iii) one black and one red.

(iv) at least one red.

* Solution: *

a) A probability tree diagram that shows all the outcomes of the experiment.

b) The probability that:

(i) **both are red.**

P(R, R) =

(ii) **both are black.
**

P(B, B) =

(iii) **one black and
one red. **

P(R, B) or P(B, R) =

(iv) **at least one
red.**

1- P(B, B) =

* Example: *

A box contains 4 red and 2 blue chips. A chip is drawn at random
and then replaced. A second chip is then drawn at random.

a) Show all the possible outcomes using a probability tree
diagram.

b) Calculate the probability of getting:

(i) at least one blue.

(ii) one red and one blue.

(iii) two of the same color.

* Solution: *

a) A probability tree diagram to show all the possible outcomes.

b) The probability of getting:

(i) **at least one
blue.**

P(R, B) or P(B, R) or P(B, B) =

(ii) **one red and one
blue.**

P(R, B) or P(B, R) =

(iii) two of the same color.

P(R, R) or P(B, B) =

The following videos give more examples of solving probability problems using probability tree diagrams.

A coin is biased so that it has a 60% chance of landing on heads.
If it is thrown three times, find the probability of getting

a) three heads

b) 2 heads and a tail

c) at least one head

Jerry has a bag with seven blue sweets and 3 red sweets in it. She picks up a sweet at random from the bag, replaces it and then picks again at random. Draw a tree diagram to represent this situation and use it to calculate the probabilities that she picks:

(a) two red sweets

(b) no red sweets

(c) at least one blue sweet

(d) one sweet of each color

Using a probability tree diagram to calculate probabilities of two
events which are not independent.

Jimmy has a bag with seven blue sweets and 3 red sweets in it.
He picks up a sweet at random from the bag, but does not replaces it and then picks again at random.
Draw a tree diagram to represent this situation and use it to calculate the probabilities that he picks:

(a) two red sweets

(b) no red sweets

(c) at least one blue sweet

(d) one sweet of each color

Inside a bag there are 3 green balls, 2 red balls and and 4 yellow balls. Two balls are randomly drawn without replacement. Calculate the probability of drawing one red ball and one yellow ball.