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This Ratio Algebra Word Problem Game/Worksheet is a great way to put your skills to the test in a fun environment. By practicing, you’ll start to work out the answers efficiently.
Ratio Algebra Word Problem Quiz/Game
This game focuses on solving word problems involving Ratios. Ratio problems including currency exchange, chemistry concentrations, engineering scales, agricultural yields, and sports statistics. Scroll down the page for a more detailed explanation.
How to Play the Ratio Algebra Explorer Game
How to Solve Ratio Algebra Word Problems
Solving ratio algebra word problems is all about translating words into a mathematical equation. Once you understand the relationship between the parts and the whole, these problems become much more manageable.
The cross-multiply method (sometimes called the “Butterfly Method”) can be used to solve ratio problems where you have two equivalent fractions and one unknown value.
The Setup: “Label and Line Up”
The most important part of cross-multiplying is making sure your units match on both sides.
\(\frac{\text{Category A}}{\text{Category B}} = \frac{\text{Category A}}{\text{Category B}}\)
If you put “Apples” on top and “Cost” on the bottom for the first ratio, you must do the same for the second.
Step-by-Step Method
Follow these four steps to solve any standard ratio problem:
Worked Example:
Scaling a Recipe
Problem: A recipe uses 3 cups of flour for every 2 cups of sugar. If you decide to use 10 cups of flour, how much sugar do you need?
Step 1: Set up the Proportion
Identify your “Base Ratio” (3:2) and your “New Ratio” (10:x).
\(\frac{3 \text{ flour}}{2 \text{ sugar}} = \frac{10 \text{ flour}}{x \text{ sugar}}\)
Step 2: Cross-Multiply
Multiply diagonally across the equals sign:
3 × x = 3x
2 × 10 = 20
This gives you the equation:
3x = 20
Step 3: Solve for x
Divide both sides by 3:
\(x = \frac{20}{3}\)
x = 6.67 cups of sugar
Solving Complex Algebraic Ratios
Sometimes the problem involves a “change” (e.g., adding more items). In these cases, you use x as a common multiplier first, then cross-multiply the new relationship.
Example: Jan and Kim have marbles in the ratio 5:6. Jan gets 2 more marbles and the new ratio is 7:8.
Original amounts: Jan = 5x, Kim = 6x.
New Ratio setup: \(\frac{5x + 2}{6x} = \frac{7}{8}\)
Cross-multiply: 8(5x + 2) = 7(6x)
Solve:
40x + 16 = 42x
16 = 2x
x = 8
Final Answer: Initially, Jan had 5(8) = 40 and Kim had 6(8) = 48.
This video gives a clear, step-by-step approach to explain how to solve ratio algebra word problems using cross multiplication.
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