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This Ratio Algebra Word Problem Game/Worksheet is a great way to put your skills to the test in a fun environment. By practicing, you’ll start to work out the answers efficiently.
Ratio Algebra Word Problem Quiz/Game
This game focuses on solving word problems involving Ratios. Ratio problems including currency exchange, chemistry concentrations, engineering scales, agricultural yields, and sports statistics. Scroll down the page for a more detailed explanation.
How to Play the Ratio Algebra Explorer Game
How to Solve Ratio Algebra Word Problems
Solving ratio algebra word problems is all about translating words into a mathematical equation. Once you understand the relationship between the parts and the whole, these problems become much more manageable.
The cross-multiply method (sometimes called the “Butterfly Method”) can be used to solve ratio problems where you have two equivalent fractions and one unknown value.
The Setup: “Label and Line Up”
The most important part of cross-multiplying is making sure your units match on both sides.
\(\frac{\text{Category A}}{\text{Category B}} = \frac{\text{Category A}}{\text{Category B}}\)
If you put “Apples” on top and “Cost” on the bottom for the first ratio, you must do the same for the second.
Step-by-Step Method
Follow these four steps to solve any standard ratio problem:
Worked Example:
Scaling a Recipe
Problem: A recipe uses 3 cups of flour for every 2 cups of sugar. If you decide to use 10 cups of flour, how much sugar do you need?
Step 1: Set up the Proportion
Identify your “Base Ratio” (3:2) and your “New Ratio” (10:x).
\(\frac{3 \text{ flour}}{2 \text{ sugar}} = \frac{10 \text{ flour}}{x \text{ sugar}}\)
Step 2: Cross-Multiply
Multiply diagonally across the equals sign:
3 × x = 3x
2 × 10 = 20
This gives you the equation:
3x = 20
Step 3: Solve for x
Divide both sides by 3:
\(x = \frac{20}{3}\)
x = 6.67 cups of sugar
Solving Complex Algebraic Ratios
Sometimes the problem involves a “change” (e.g., adding more items). In these cases, you use x as a common multiplier first, then cross-multiply the new relationship.
Example: Jan and Kim have marbles in the ratio 5:6. Jan gets 2 more marbles and the new ratio is 7:8.
Original amounts: Jan = 5x, Kim = 6x.
New Ratio setup: \(\frac{5x + 2}{6x} = \frac{7}{8}\)
Cross-multiply: 8(5x + 2) = 7(6x)
Solve:
40x + 16 = 42x
16 = 2x
x = 8
Final Answer: Initially, Jan had 5(8) = 40 and Kim had 6(8) = 48.
This video gives a clear, step-by-step approach to explain how to solve ratio algebra word problems using cross multiplication.
Try out our new and fun Fraction Concoction Game.
Add and subtract fractions to make exciting fraction concoctions following a recipe. There are four levels of difficulty: Easy, medium, hard and insane. Practice the basics of fraction addition and subtraction or challenge yourself with the insane level.
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