Motion Algebra Word Problem Game


 

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This Motion Algebra Word Problem Game/Worksheet is a great way to put your skills to the test in a fun environment. By practicing, you’ll start to work out the answers efficiently.
 




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Motion Algebra Word Problem Quiz/Game
This game focuses on solving word problems involving Motions. Motion problems including catching up, opposite directions, and current/wind problems. Scroll down the page for a more detailed explanation.


 


 

How to Play the Motion Algebra Explorer Game

  1. Look at the Problem: Read the problem carefully. Solve it and select one of the answers.
  2. Check Your Work: If you selected the right answer, it will be highlighted in green. If you are wrong, it will be highlighted in red and the correct answer will be highlighted in green. A hint will be given to help you find the correct answer.
  3. Get a New Problem: Click “Next Question” for a new problem.
    Your score is tracked, showing how many you’ve gotten right.
  4. Finish Game When you have completed 10 questions, your final score will be displayed.
     

How to Solve Motion Algebra Word Problems
Most motion problems rely on the fundamental formula:
d = r × t
(Distance = Rate × Time)

Common Scenario Types
A. Opposite Directions (Total Distance)
The Setup: Two objects start at the same point and move away, or start far apart and move toward each other.
The Equation: Add the distances together to equal the total.

d1 + d2 = Total Distance

B. Catch-Up (Equal Distance)
The Setup: One object leaves, and a faster object leaves later to “catch” it.
The Equation: Since they meet at the same spot, their distances are equal.

r1 t1 = r2 t2

C. Round Trips
The Setup: An object goes to a destination and returns.
The Equation: The distance going is equal to the distance returning.
Note: Rates usually change due to wind, current, or effort.

rgo tgo = rreturn treturn

Step-by-Step Example
Problem: A train leaves at 60 mph. Two hours later, a faster train leaves at 80 mph on a parallel track. How long until the second train catches the first? Identify the variable: Let t be the time for the faster train.
Define the other time: The slower train has been traveling longer, so its time is t + 2.

Train 1: d = 60(t + 2)
Train 2: d = 80(t)
Create the equation: 60(t + 2) = 80t

Solve:
60t + 120 = 80t
120 = 20t
t = 6

Answer: 6 hours.
 

This video gives a clear, step-by-step approach to explain how to solve motion algebra word problems.


 

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