 # SAT Practice Test 2, Section 9: Questions 1 - 5

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Math Worksheets

This is for SAT in Jan 2016 or before.

The following are worked solutions for the questions in the math sections of the SAT Practice Tests found in the The Official SAT Study Guide Second Edition .

It would be best that you go through the SAT practice test questions in the Study Guide first and then look at the worked solutions for the questions that you might need assistance in. Due to copyright issues, we are not able to reproduce the questions, but we hope that the worked solutions will be helpful.

Given:
Starts with same number of boys and girls on a school bus
At the first stop, 4 boys got off
Then, there are twice as many girls as boys on the bus

To find:
The number of girls on the bus

Solution:
Topic(s): Integer problems

Let x = girls

x – 4 = boys (4 boys got off the bus)

Twice as many girls as boys.

x = 2(x – 4)
x = 2x – 8
x = 8

To find:
The graph of a linear function with a negative slope and positive y-intercept

Solution:
Topic(s): Equation of a line

A negative slope means that the line will slope down from left to right. This eliminates (A) and (B).

A positive y-intercept means that the line will intersect the y-axis at a positive value. This eliminates (C) and (E). The correct answer is then (D).

Given:
A price list

To find:
Approximate cost of donut in a box of 6

Solution:

 Number of Donuts Total Price 1 \$0.40 Box of 6 \$1.89 Box of 12 \$3.59

For a box of 6, the cost per donut would be The closest approximation is 0.30

Given:
A price list

To find:
Least amount of money needed to buy 21 donuts

Solution:
In order, to purchase 21 donuts with the least amount of money we would need to buy the cheaper packages whenever possible.

21 = 12 + 6 + 3

We need to buy 1 box of 12, 1 box of 6 and 3 single donuts.

Box of 12 = \$3.59
Box of 6 = \$1.89

3 donuts = 3 × \$0.40 = \$1.20

Total cost = \$3.59 + \$1.89 + \$1.20 = \$6.68

Given:
Graph of function h

To find:
h(5)

Solution:
Topic(s): Coordinate geometry

Read the graph at x = 5.

Draw a vertical line from x = 5 to the graph.

Draw a horizontal line from that point on the graph to the y-axis.

It meets the y-axis at 3

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