In these lessons, we will look at some examples of simplifying fractions within a square root (or radical). Some techniques used are find the square root of the numerator and denominator separately, reduce the fraction and change to improper fraction.

Related Topics:

More Lessons on Fractions , Fraction Worksheets, Fraction Games

**A.** The square root of some fractions can be determined by finding the square root of the numerator and denominator separately.

**Example:**

\(\sqrt {\frac{{16}}{{25}}} = \frac{{\sqrt {16} }}{{\sqrt {25} }} = \frac{{\sqrt {{4^2}} }}{{\sqrt {{5^2}} }} = \frac{4}{5}\)

For any positive number *x* and *y,*

\(\sqrt {\frac{x}{y}} = \frac{{\sqrt x }}{{\sqrt y }}\)

In other words, the square root of a fraction is a fraction of square roots.**B.** Some fractions can be reduced to fractions with perfect squares as the numerator and denominator. Then the square root of such fraction can be seen as shown in the example below.

**Example:**

\(\sqrt {\frac{{18}}{{50}}} = \sqrt {\frac{9}{{25}}} = \frac{{\sqrt {{3^2}} }}{{\sqrt {{5^2}} }} = \frac{3}{5}\)

**C.** For a positive mixed number, change it to an improper fraction before finding the square root.

**Example:**

\(\sqrt {1\frac{{13}}{{36}}} = \sqrt {\frac{{49}}{{36}}} = \frac{{\sqrt {{7^2}} }}{{\sqrt {{6^2}} }} = \frac{7}{6} = 1\frac{1}{6}\)

* Example: *

Calculate the value of each of the following:

\(\begin{array}{l}{\rm{a)}}\,\,\sqrt {\frac{{25}}{{36}}} \\{\rm{b)}}\,\,\sqrt {\frac{{18}}{{32}}} \\{\rm{c)}}\,\,\sqrt {1\frac{{11}}{{25}}} \end{array}\)

* Solution: *

a) Work out the square roots of the numerator and denominator separately.

\(\begin{array}{c}\sqrt {\frac{{25}}{{36}}} = \frac{{\sqrt {25} }}{{\sqrt {36} }}\\ = \frac{{\sqrt {{5^2}} }}{{\sqrt {{6^2}} }}\\ = \frac{5}{6}\end{array}\)

b) Reduce the fraction first.

\(\begin{array}{c}\sqrt {\frac{{18}}{{32}}} = \sqrt {\frac{9}{{16}}} \\ = \frac{{\sqrt 9 }}{{\sqrt {16} }}\\ = \frac{{\sqrt {{3^2}} }}{{\sqrt {{4^2}} }}\\ = \frac{3}{4}\end{array}\)

c) Change to improper fraction first.

\(\begin{array}{c}\sqrt {1\frac{{11}}{{25}}} = \sqrt {\frac{{36}}{{25}}} \\ = \frac{{\sqrt {36} }}{{\sqrt {25} }}\\ = \frac{{\sqrt {{6^2}} }}{{\sqrt {{5^2}} }}\\ = \frac{6}{5}\\ = 1\frac{1}{5}\end{array}\)

Square Roots of Fractions/Rational Numbers

Finding the square of rational numbers for perfect squares as well as estimating non-perfect squares.

An introduction to the quotient rule for square roots and radicals and how to use it to simplify expressions containing radicals.

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