There are several techniques that can be used to factor quadratic equations.

In this lesson, we will learn how to factor quadratic equations, where the coefficient of*x*^{2} is greater than 1, using the trial and error method. In this method, we will need to try out different possibilities to get the
right factors for the given quadratic equation. In this lesson, we will also learn how to factor quadratic equations by grouping

We also have another lesson that will show you how to factor quadratic equations without trial and error.

Related Topics:

Other Factoring Techniques, More Algebra Lessons

### If the Coefficient of *x*^{2} Is Greater Than 1

* x* = 2, *x* = 5

Example 2: Get the values of *x* for the equation 7*x*^{2} + 18*x* + 11 = 0

Example 3: Get the values of *x* for the equation 4*x*^{2} + 26*x* + 12 = 0

This video explains how to solve quadratic equations by factoring.
The following video shows an example of factoring a quadratic:
Solving Quadratic Equations by Factoring.

### Factoring Quadratic Equations by Grouping

Factoring by Grouping - 3 complete examples of solving quadratic equations using factoring by grouping are shown.
Solving Quadratic Equations by Factoring Using the Grouping Method.

Ex 1: Factor and Solve a Quadratic Equation - Factor by Grouping.
This video provides two examples how to factor and solve a quadratic equation by using the factor by grouping method.
Related Topics:

Factoring Out Common Factors (GCF).

Factoring Quadratic Equations using Perfect Square Trinomial (Square of a Sum or Square of a Difference) or Difference of Two Squares.

Factoring Quadratic Equations where the coefficient of*x*^{2 }is 1.

Factoring Quadratic Equations by Completing the Square

Factoring Quadratic Equations using the Quadratic Formula.

You can use the free Mathway calculator and problem solver below to practice Algebra or other math topics. Try the given examples, or type in your own problem and check your answer with the step-by-step explanations.

In this lesson, we will learn how to factor quadratic equations, where the coefficient of

We also have another lesson that will show you how to factor quadratic equations without trial and error.

Related Topics:

Other Factoring Techniques, More Algebra Lessons

Sometimes the coefficient of *x* in quadratic equations may not be 1, but the expression can be simplified by first finding common factors.

When the coefficient of *x*^{2} is greater than 1 and we cannot simplify the quadratic equation by finding common factors, we would need to consider the factors of the coefficient of *x*^{2} and the factors of *c* in order to get the numbers whose sum is *b*. If there are many factors to consider you may want to use the quadratic formula instead.

Example 1: Get the values of *x* for the equation 2*x*^{2} – 14*x* + 20 = 0

Step 1: Find common factors if you can.

2

x^{2}– 14x+ 20 = 2(x^{2}– 7x+ 10)

Step 2: Find the factors of (*x*^{2} – 7*x* + 10)

List out the factors of 10:

We need to get the negative factors of 10 to get a negative sum.

–1 × –10, –2 × –5

Step 3: Find the factors whose sum is – 7:

1 + ( –10) ≠ –7

–2 + ( –5) = –7

Step 4: Write out the factors and check using the distributive property.

2(

x– 2) (x– 5) = 2(x^{2}– 5x– 2x+ 10)

= 2(x^{2}– 7x+ 10) = 2x^{2}– 14x+ 20

Step 5: Going back to the original equation

Answer:2

x^{2}– 14x+ 20 = 0 Factorize the left hand side of the equation

2(x– 2) (x– 5) = 0We get two values for

x

Step 1: List out the factors of 7 and 11

Factors of 7:

1 × 7Factors of 11:

1 × 11Since 7 and 11 are prime numbers there are only two possibilities to try out.

Step 2: Write down the different combinations of the factors and perform the distributive property to check.

(7

x +1)(x+ 11) ≠ 7x^{2}+ 18x+ 11

(7x +11)(x+ 1) = 7x^{2}+ 18x+ 11

Step 3: Write out the factors and check using the distributive property.

(7

x +11)(x+ 1) = 7x^{2}+ 7x+ 11x+ 11 = 7x^{2}+ 18x+ 11

Step 4: Going back to the original equation

7

x^{2}+ 18x+ 11= 0 Factorize the left hand side of the equation

(7x +11)(x+ 1) = 0We get two values for

x

Answer:

Step 1: Find common factors if you can.

4

x^{2}+ 26x+ 12 = 2(2x^{2}+ 13x+ 6)

Step 2: List out the factors of 2 & 6

Factors of 2:

1 × 2Factors of 6:

1 × 6, 2 × 3

Step 3: Write down the different combinations of the factors and perform the distributive property to check. When there are many factors to check, this becomes a tedious method to solve such quadratic equations, so you may want to try the quadratic formula instead.

(

x +1)(2x+ 6) ≠ (2x^{2}+ 13x+ 6)

(x +6)(2x+ 1) = (2x^{2}+ 13x+ 6)

Step 4: Going back to the original quadratic equation

4

x^{2}+ 26x+ 12 = 0 Factorize the left side of the equation

2(x +6)(2x+ 1) = 0We get two values for

x

Answer:

This video explains how to solve quadratic equations by factoring.

Factoring Out Common Factors (GCF).

Factoring Quadratic Equations using Perfect Square Trinomial (Square of a Sum or Square of a Difference) or Difference of Two Squares.

Factoring Quadratic Equations where the coefficient of

Factoring Quadratic Equations by Completing the Square

Factoring Quadratic Equations using the Quadratic Formula.

Rotate to landscape screen format on a mobile phone or small tablet to use the **Mathway** widget, a free math problem solver that **answers your questions with step-by-step explanations**.

You can use the free Mathway calculator and problem solver below to practice Algebra or other math topics. Try the given examples, or type in your own problem and check your answer with the step-by-step explanations.

We welcome your feedback, comments and questions about this site or page. Please submit your feedback or enquiries via our Feedback page.