Related Topics: More Lessons on Probability

A

In these lessons, we will learn the permutation formula for the number of permutations of

In general P(

The formula for permutation is

If you are not familiar with the *n*! (*n* factorial notation) then have a look the factorial lesson.

**Example:**

A license plate begins with three letters. If the possible letters are A, B, C, D and E, how many different permutations of these letters can be made if no letter is used more than once?

*Solution: *

**Using reasoning:**

For the first letter, there are 5 possible choices. After that letter is chosen, there are 4 possible choices. Finally, there are 3 possible choices.

5 × 4 × 3 = 60

**Using the permutation formula:**

The problem involves 5 things (A, B, C, D, E) taken 3 at a time.

There are 60 different permutations for the license plate.

*Example: *

In how many ways can a president, a treasurer and a secretary be chosen from among 7 candidates?

*Solution: *

**Using reasoning:**

For the first position, there are 7 possible choices. After that candidate is chosen, there are 6 possible choices. Finally, there are 5 possible choices.

7 × 6 × 5 = 210

** Using permutation formula: **

The problem involves 7 candidates taken 3 at a time.

There are 210 possible ways to choose a president, a treasurer and a secretary be chosen from among 7 candidates

*Example: *

A zip code contains 5 digits. How many different zip codes can be made with the digits 0–9 if no digit is used more than once and the first digit is not 0?

*Solution: *

**Using reasoning:**

For the first position, there are 9 possible choices (since 0 is not allowed). After that number is chosen, there are 9 possible choices (since 0 is now allowed). Then, there are 8 possible choices, 7 possible choices and 6 possible choices.

9 × 9 × 8 × 7 × 6 = 27,216

** Using permutation formula: **

We can’t include the first digit in the formula because 0 is not allowed.

For the first position, there are 9 possible choices (since 0 is not allowed). For the next 4 positions, we are selecting from 9 digits.

The following video provides some information on permutations and how to solve some word problems using permutations.

In this video, we will learn how to evaluate factorials, use permutations to solve problems, determine the number of permutations with indistinguishable items.

Basic info on permutations and word problems using permutations are shown.

Introduction to permutations.

Permutations Involving Repeated Symbols - Example 1.

This video shows how to calculate the number of linear arrangements of the word MISSISSIPPI (letters of the same type are indistinguishable). It gives the general formula and then works out the exact answer for this problem.

In this example, we count how many 'stair-case' paths there are from the origin to the point (5,3).

Permutations with restrictions : items not together

1) In how many ways can five men and three women be arranged in a row if no two women is standing nest to one another?

2) In how many ways can the word "SUCCESS" be arranged if no two S's are next to on another?

2) How many ways can the letters in the word 'PARALLEL" be arranged if the letters P and R are together?

Permutations Vs Combinations

This video highlights the differences between permutations and combinations and when to use each of them.

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