The following example shows how to determine the mean from frequency table with intervals.
Example:
The following table shows the frequency distribution of the diameters of 40 bottles. (Lengths have been measured to the nearest millimetre.) Find the mean of the data.
Diameter (mm)
35 – 39
40 – 44
45 – 49
50 – 54
55 – 60
Frequency
6
12
15
10
7
Solution:
Step 1: Find the midpoint of each interval.
Midpoint of interval = (Lower class limit + Upper class limit)
= (39 + 35) = 37
Diameter (mm)
35 – 39
40 – 44
45 – 49
50 – 54
55 – 60
Frequency (f)
6
12
15
10
7
Mid-point (x)
37
42
47
52
57
Step 2: Multiply the frequency of each interval by its mid-point
Diameter (mm)
35 – 39
40 – 44
45 – 49
50 – 54
55 – 60
Frequency (f)
6
12
15
10
7
Mid-point (x)
37
42
47
52
57
f × x
222
504
705
520
399
Step 3: Get the sum of all the frequencies (f) and the sum of all the fx. Divide ‘sum of fx’ by ‘sum of f ’ to get the mean.
Total
Diameter (mm)
35 – 39
40 – 44
45 – 49
50 – 54
55 – 60
Frequency (f)
6
12
15
10
7
50
Mid-point (x)
37
42
47
52
57
f × x
222
504
705
520
399
2350
The following video shows how to find the mean, mode and median from a frequency table for both discrete and grouped data
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