Lessons on solving age word problems, for Algebra students in Grades 9-10.
Here you will be learning how to solve “age” word problems, such as the following:
Bret is 3 times as old as Laura. In 5 years, Bret will be twice as old as Laura. Find their ages now.
Note that this problem requires a chart to organize the information. The rows of the chart can be labeled as Laura and Bret, and the columns of the chart can be labeled as “age now” and “age in 5 years”. The chart is then used to set up the equation.
A man is 21 years older than his son. Five years ago he was 4 times as old as his son. What are their ages now?
A man is 6 years older than 3 times his son’s age. Five years from now the sum of their ages will be 56. How old are they now?
A man is 6 times as old as his son. In 3 years he will be 4 times as old. How old are the man and his son?
5 years ago a dad was 6 years older than 3 times his son’s age at that time. In 4 years, he will be 5 years older than twice the age of his son. How old are they now?
The video gives a suggested solution.
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