**11. Correct answer: (C)**

Given:

The table

To find:

Car engine oil with a rating of 5W is how many times as fast as car engine oil with rating of 20W

Solution:

From the table;

5W = 2 × 10W

10W = 2 × 15W

15W = 2 × 20W

This means that

5W = 2 × 10W

= 2 × 2 × 15W

= 2 × 2 × 2 × 20W

=
8 × 20W

**Answer: (C) 8**

**12. Correct answer: (E)**

Given:

The figure

Points *P, A* and *B* are equally spaced on line *l
*Points

* PB* = 4

*PR = *6

*AQ = 4*

To find:

Perimeter of *QABR *

Solution:**
**Topic(s): RAR rule

Triangles *PAQ* and *PBR* are similar triangles (RAR)

The ratio of the sides is the same.

The perimeter of the quadrilateral *QABR* = 4 + 2 + 3 + 8 = 17

**Answer: (E) 17**

**13. Correct answer: (D)**

Given:

*g*(*n*) = *n*^{2} + *n*

*h*(*n*) = *n*^{2} − *n*

To find:

*g*(5) - *h*(4)

Solution:

*g*(5) = 52 + 5 = 30

*h*(4) = 42 − 4 = 12

*g*(5) − *h*(4) = 30 −12 = 18

**Answer; (D) 18**

**14. Correct answer: (A)**

Given:

*g*(*n*) = *n*^{2} + *n*

*h*(*n*) = *n*^{2} − *n*

To find:

*h*(*m* + 1)

Solution:

*h*(*m* + 1)

= (*m* + 1)^{2} − (*m* + 1)

= *m*^{2}* + *2*m + *1* − **m* − 1

= *m*^{2} + *m*

= *g*(*m*)

**Answer: (A) g(m)**

**15. Correct answer: (B)**

Given:

The selling price of a sweater = $28

The selling price is 40% more than the cost price

Employees can purchase the sweater at 30% off the cost price

To find:

The amount the employees pay for the sweater

Solution:

Topic(s): Percent

Let *c* be the cost price of the sweater.

*c* + 40% × *c* = 28

*c* + 0.4*c* = 28

1.4*c* = 28

*c* = 20

Purchase price = 20 − 30% × 20

= 20 − 0.3 × 20

= 20 − 6

= 14

**Answer: (B) $14.00**

**16. Correct answer: (C)**

Given:

A rectangle *ABCD
*Point

Area of

To find:

Area of *ABCD *

Solution:

Topic(s): Area of trapezium

Let *AB* = *l * and *BE* = *w*

Area of trapezium *ABED* =

Area of rectangle *ABCD = *

**Correct answer: (C)**

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