Solve the quadratic inequality x2 – 4x > –3
Step 1: Make one side of the inequality zerox2 – 4x > –3
Step 2: Factor the quadratic expressionx2 – 4x + 3 > 0
Note: If the quadratic inequality was (x – 3)(x – 1) < 0 (y is negative), we would have chosen the interval for which the curve is below the x-axis i.e. 1 < x < 3
The following graphs show the solutions for x2 – 4x + 3 > 0 and x2 – 4x + 3 < 0. Scroll down the page for more examples and solutions.
Solve 2x2 < 9x + 5
Step 1: Make one side of the inequality zero2x2 < 9x + 5
Step 2: Factor the quadratic expression2x2 – 9x – 5 < 0
Step 3: Find the range of values of x which satisfies the inequality.(2x + 1)(x – 5) < 0 (y is negative): we choose the interval for which the curve is below the x-axis.
Note: If the quadratic inequality was (2x + 1)(x – 5) > 0 (y is positive) we would have chosen the interval for which the curve is above the x-axis i.e. or x > 5
How to solve quadratic inequalities?
Guidelines for solving Quadratic Inequalities
1. Find all the zeros of the polynomial, and arrange the zeros in increasing order. The zeros are called its critical numbers.
2. Plot those numbers on the number line as open or closed points based upon the original inequality symbol.
3. Choose a test value in each interval to see if the interval satisfies the inequality or not. If the test value produces a true statement, the entire interval will be true. If the interval produces a false statement, the entire interval is false.
4. Clearly graph your solution and state the solution using interval notation or inequalities.
1. Solve x2 - 6x - 16 ≤ 0
2. Solve 2x2 - 11x + 12 > 0
3. Solve x2 + 4 > 0
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