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Exercises for Lesson 26
Given: π΄π΅ β₯ π΅πΆ, π΅πΆ β₯ π·πΆ
π·π΅ bisects β π΄π΅πΆ, π΄πΆ bisects β π·πΆπ΅
πΈπ΅ = πΈπΆ
Prove: β³ π΅πΈπ΄ β
β³ πΆπΈπ·
Given: π΅πΉ β₯ π΄πΆ, πΆπΈ β₯ π΄π΅
π΄πΈ = π΄πΉ
Prove: β³ π΄πΆπΈ β
β³ π΄π΅πΉ
Given: ππ½ = ππΎ, ππ = ππ, πβ πππ½ = πβ πππΎ
Prove: π½π = πΎπ
Given: π½πΎ = π½πΏ, π½πΎ β₯ ππ
Prove: ππ = ππΏ
Given: β 1 β
β 2, β 3 β
β 4
Prove: π΄πΆ β
π΅π·
Given: πβ 1 = πβ 2, πβ 3 = πβ 4, π΄π΅ = π΄πΆ
Prove: (a) β³ π¨π©π« β
β³ π¨πͺπ«
(b) πβ π = πβ 6
Exercises for Lesson 27
Given: π΄π΅ = π΄πΆ, π
π΅ = π
πΆ
Prove: ππ΅ = ππΆ
Given: Square π΄π΅πΆπ β
Square πΈπΉπΊπ,
π
π΄π΅, π
πΈπΉ
Prove: β³ π΄ππ
β
β³ πΈππ
Given: π½πΎ = π½πΏ,π½π = π½π
Prove: πΎπ = πΏπ
Given: π΄π· β₯ π·π
, π΄π΅ β₯ π΅π
,
π΄π· β
π΄π΅
Prove: β π·πΆπ
β
β π΅πΆπ
Given: π΄π
= π΄π, π΅π
= πΆπ,
π
π β₯ π΄π΅, ππ β₯ π΄πΆ
Prove: π΅π = πΆπ
Given: π΄π = π΅π, πβ π΄ππ΅ = πβ π΄ππ = 90Β°
Prove: ππ = ππ
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