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Area of Parallelograms
Let’s practice finding the area of parallelograms.
Illustrative Math Unit 6.1, Lesson 6 (printable worksheets)
6.1 - Missing Dots
How many dots are in the image? How do you see them? Can you do this without counting the dots?
The dots are regularly-spaced and are all the same size. Think of the dots as shaded squares in a grid showing the area of a figure.
The dots make up a square that is 6 by 6 dots, minus the space in the middle that is 3 by 2 dots. Hence, there are (6 × 6) - (3 × 2) = 30 dots.
Notice that this is similar to what you would do to find the area of a figure with these dimensions.
6.2 - More Areas of Parallelograms
A. Calculate the area of the given figure in the applet. Then, check if your area calculation is correct by clicking the Show Area checkbox.
B. Uncheck the Area checkbox. Move one of the vertices of the parallelogram to create a new parallelogram. When you get a parallelogram that you like, sketch it and calculate the area. Then, check if your calculation is correct by using the Show Area button again.
C. Repeat this process two more times. Draw and label each parallelogram with its measurements and the area you calculated.
First find the area of the parallelogram using the base and height that are provided. The area of the parallelogram remains the same when a different side is used as a base.
The area of the parallelogram is 15 cm × 8 cm = 120 square cm.
The area of the parallelogram remains the same when a different side is used as a base, so 120 square cm = 10 cm × h
h = 120 square cm ÷ 10 cm
h = 12 cm
A: Explain why their areas are equal.
B: Drag points to create two new parallelograms that are not identical copies of each other but that have the same area as each other. Sketch your parallelograms and explain or show how you know their areas are equal. (Note that the Check button in the applet is affected by minor mismatches of your parallelograms with the grid.)
The formula to find the area of a parallelogram is A = b · h.To draw parallelograms with the same area, find pairs of different bases and heights that have the same product.
A: Calculating the areas of the two parallelograms using their bases and heights gives the same result:
Left: 6 × 4 = 24 square units
Right: 3 × 8 = 24 square units
Another way to show this is that parallelogram on the right can be decomposed and rearranged into a parallelogram with the same base and height as the one on the left.
B: These are examples of two parallelograms that are not identical but have the same area as each other.
Left: 3 units × 4 units = 12 square units
Right: 2 units × 6 units = 12 square units
Here is a parallelogram composed of smaller parallelograms. The shaded region is composed of four identical parallelograms. All lengths are in inches.
What is the area of the unshaded parallelogram in the middle? Explain or show your reasoning.
One way to find the area of the unshaded region is to find the total area of the small parallelograms, and then subtract this from the area of the large parallelogram. What information do you need to find the area of the large parallelogram?
To help you find this information, find the area of one of the small parallelograms. When you know the area, you can choose another side of a small parallelogram to be the base and find the new height. Mark all the heights of the small parallelograms.
One way to find the area of the unshaded region is to find the total area of the small parallelograms, and then subtract this from the area of the large parallelogram. The area of a small parallelogram is 5 × 2.4 = 12 square inches, so the total area of the shaded region is 4 × 12 = 48 square inches.
To find the area of the large parallelogram, we need the base and height.
If a small parallelogram has an area of 12 square inches, and we choose the 3-inch side as the base, the red dashed line is the new height. This dashed line is 12 ÷ 3 = 4 inches.
To this red line, we can add the first height we used for the small parallelograms (2.4 inches), labeled in blue. This gives us a full height for the large parallelogram: 4 + 2.4 = 6.4 inches.
The base of the large parallelogram is 5 + 3 = 8 inches. Hence, the area of the large parallelogram is 8 × 6.4 = 51.2 square inches.
The area of the unshaded region is 51.2 - 48 = 3.2 square inches.
Lesson 6 Summary
Any corresponding pair of base and height can help us find the area of a parallelogram, but some base-height pairs are more easily identified than others.
When a parallelogram is drawn on a grid and has horizontal sides, we can use a horizontal side as the base. When it has vertical sides, we can use a vertical side as the base. The grid can help us find (or estimate) the lengths of the base and of the corresponding height.
When a parallelogram is not drawn on a grid, we can still find its area if a base and a corresponding height are known.
In this parallelogram, the corresponding height for the side that is 10 units long is not given, but the height for the side that is 8 units long is given. This base-height pair can help us find the area.
Regardless of their shape, parallelograms that have the same base and the same height will have the same area; the product of the base and height will be equal. Here are some parallelograms with the same pair of base-height measurements.
A, B, and D have the same area, as they have the same values for their bases and heights.
A: 5 × 3 = 15 square units
B: 3 × 5 = 15 square units
C: 4 × 4 = 16 square units
D: 3 × 5 = 15 square units
A: b = 4, h = 3.5
B: b = 0.8, h = 20
C: b = 6, h = 2.25
D: b = 10, h = 1.4
A: 4 cm × 3.5 cm = 14 square cm
B: 0.8 cm × 20 cm = 16 square cm
C: 6 cm × 2.25 cm = 13.5 square cm
D: 10 cm × 1.4 cm = 14 square cm
B produces the greatest area.
A: 10 square units ÷ 5 units = 2 units
B: 21 square units ÷ 7 units = 3 units
C: 25 square units ÷ 5 units = 5 units
Note that while dashed lines have been added to extend the bases of B and C to meet the height, the length of the base extension is not necessary to find the base.
86 meters × 55 meters = 4730 square meters
e, f, j, and k are all perpendicular to the base m and could represent its corresponding height.
First, find the area of the large rectangle. Then, is it possible to find the area of the unshaded regions?
The area of the large rectangle is (12 + 2) × (6 + 4) = 140 square centimeters.
The unshaded regions are triangles which can be rearranged into rectangles.
The total area of the unshaded regions is (2 × 6) + (12 × 4) = 60 square centimeters.
Hence, the area of the shaded region is 140 - 60 = 80 square centimeters.
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