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More Lessons for Passport to Advanced Math

More Lessons for SAT Math

More Resources for SAT

Algebra Tutorials

This video is for the redesigned SAT, which is for you, if you are taking the SAT in March 2016 and beyond.

Calculator: Permitted

Passport to Advanced Math

**How to analyze equations and functions in context?**

v = v_{0} - gt

h = v_{0}t - 1/2 gt^{2}

v^{2} = v_{0}^{2} - 2gh

An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acceleration motion of the arrow, where v_{0} is the initial speed of the arrow, v is the speed of the arrow as it is moving up in the air, h is the height of the arrow above the ground, t is the time elapsed since the arrow was projected upward, and g is the acceleration due to gravity (9.8 m/s^{2}).

Part 1: What is the maximum height from the ground the arrow will rise to the nearest meter?

Part 2: How long will it take for the arrow to reach its maximum height to the nearest tenth of a second?

(Errata: The parabola shown in the video does not represent the "trajectory" of the arrow. It represents the height or vertical displacement (from the ground) of the arrow. Thanks Margaret for pointing out the error.)

More Lessons for Passport to Advanced Math

More Lessons for SAT Math

More Resources for SAT

Algebra Tutorials

This video is for the redesigned SAT, which is for you, if you are taking the SAT in March 2016 and beyond.

Calculator: Permitted

Passport to Advanced Math

v = v

h = v

v

An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acceleration motion of the arrow, where v

Part 1: What is the maximum height from the ground the arrow will rise to the nearest meter?

Part 2: How long will it take for the arrow to reach its maximum height to the nearest tenth of a second?

(Errata: The parabola shown in the video does not represent the "trajectory" of the arrow. It represents the height or vertical displacement (from the ground) of the arrow. Thanks Margaret for pointing out the error.)

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