Algebra: Ticket Word Problems
Ticket problems are word problems similar to coin problems and
stamp problems as tickets may be denominated in specific values.
Be careful to distinguish between the value of the items and the quantity of the
items. A table is useful for distinguishing between
quantity and value
in this type of word problems.
Example 1:
The cost of tickets for a play is $3.00 for adults and $2.00 for children. 350 tickets were sold and $950 was collected. How many tickets of each type were sold?
Solution:
Step 1: Set up a table with quantity and value.
|
quantity |
value |
total |
$3 tickets |
|
|
|
$2 tickets |
|
|
|
together |
|
|
|
Step 2: Fill in the table with information from the question.
The cost of tickets for a play is $3.00 for adults and $2.00 for children. 350 tickets were sold and $950 was collected. How many tickets of each type were sold?
| Let |
x = |
number of $3 tickets |
| |
y = |
number of $2 tickets |
| |
Total = |
quantity × value |
|
quantity |
value |
total |
$3 tickets |
x |
3 |
3x |
$2 tickets |
y |
2 |
2y |
together |
350 |
|
950 |
Step 3: Add down each column to get the equations
x + y = 350 (equation 1)
3x + 2y = 950 (equation 2)
Use Substitution Method
Isolate variable x in equation 1
x = 350 – y (equation 3)
Substitute equation 3 into equation 2
3(350 – y) + 2y = 950
1050 – 3y + 2y = 950
3y – 2y = 1050 – 950
y = 100
Substitute y = 100 into equation 1
x + 100 = 350
x = 250
Answer: 250 $3 tickets and 100 $2 tickets were sold.
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