In this lesson, we will learn how to solve cubic equations using the Remainder Theorem and the Factor Theorem.

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**What is the Remainder Theorem?**

If a polynomial, f(x), is divided by x - k, the remainder is equal to f(k).

**What is the Factor Theorem?**

x - k is a factor of the polynomial f(x) if and only if f(k) = 0

**How to solve cubic equations using the Factor Theorem?**

In these lessons, we will consider how to solve cubic equations of the form

*px*^{3} + *qx*^{2} + *rx* + *s* = 0 where *p, q, r * and *s* are constants by using the Factor Theorem and Synthetic Division.

f(–1) = –2 + 3 + 11 – 6 ≠ 0

f(2) = 16 + 12 – 22 – 6 = 0

We find that the integer root is 2.

Step 2: Find the other roots either by inspection or by synthetic division.

**How to use the Factor Theorem to factor polynomials?**

Examples:

1) Factor P(x) = 3x^{3} − x^{2} − 10x + 8

2) Factor P(x) = 2x^{3} − 9x^{2} + x + 12
**What are The Remainder Theorem and the Factor Theorem?**

How to use the Theorems to find the linear factorization of a polynomial?

Example: Factor F(x) = 2x^{3} − 3x^{2} − 5x + 6
**How to use the Factor Theorem to solve a cubic equation?**

If f(x) is a polynomial and f(p) = 0 then x - p is a factor of f(x)

Example: Solve the equation 2x^{3} −5x^{2} − 10 = 23x

**How to solve Cubic Equations using the Factor theorem and Long Division?**

Example: Find the roots of the cubic equation 2x^{3} − 6x^{2} + 7x − 1 = 0
**How to solve Cubic Equations using the Factor theorem and Synthetic Division?**

Example: Show that x + 3 is a factor of x^{3} − 19x − 30 = 0. Then find the remaining factors of f(x)
**How to solve cubic equation problems?**

Example: 3x^{3} −4x^{2} − 17x = x^{3} + 3x^{2} − 10

Step 1: Set one side of equation equal to 0.

Step 2: Collect like terms.

Step 3: Factorize using the Factor Theorem and Long Division

You can use the free Mathway calculator and problem solver below to practice Algebra or other math topics. Try the given examples, or type in your own problem and check your answer with the step-by-step explanations.

Related Topics:

More Algebra Lessons

More Algebra Worksheets

More Algebra Games

If a polynomial, f(x), is divided by x - k, the remainder is equal to f(k).

x - k is a factor of the polynomial f(x) if and only if f(k) = 0

In these lessons, we will consider how to solve cubic equations of the form

**Example:**

Find the roots of f(*x*) = 2x^{3} + 3*x*^{2} – 11*x* – 6 = 0, given that it has at least one integer root.

**Solution:**

Since the constant in the given equation is a 6, we know that the integer root must be a factor of 6. The possible values are

Step 1: Use the factor theorem to test the possible values by trial and error.

f(1) = 2 + 3 – 11 – 6 ≠ 0f(–1) = –2 + 3 + 11 – 6 ≠ 0

f(2) = 16 + 12 – 22 – 6 = 0

We find that the integer root is 2.

Step 2: Find the other roots either by inspection or by synthetic division.

2x^{3} + 3*x*^{2} – 11*x* – 6

= (*x* – 2)(*ax*^{2} + *bx + c*)

= (*x* – 2)(2*x*^{2} + *bx + *3)

= (*x* – 2)(2*x*^{2} + 7*x + *3)

= (*x* – 2)(2*x* + 1)(*x* +3)

So, the roots are

** Example: **

Solve the cubic equation *x*^{3} – 7*x*^{2} + 4*x* + 12 = 0

** Solution: **

Let f(*x*) = *x*^{3} – 7*x*^{2} + 4*x* + 12

We find that f(–1) = –1 – 7 – 4 + 12 = 0

So, (*x* + 1) is a factor of f(*x*)

* **x*^{3} – 7*x*^{2} + 4*x* + 12

= (*x* + 1)(*x*^{2} – 8*x* + 12)

= (*x* + 1)(*x* – 2)(*x* – 6)

Examples:

1) Factor P(x) = 3x

2) Factor P(x) = 2x

How to use the Theorems to find the linear factorization of a polynomial?

Example: Factor F(x) = 2x

If f(x) is a polynomial and f(p) = 0 then x - p is a factor of f(x)

Example: Solve the equation 2x

Example: Find the roots of the cubic equation 2x

Example: Show that x + 3 is a factor of x

Example: 3x

Step 1: Set one side of equation equal to 0.

Step 2: Collect like terms.

Step 3: Factorize using the Factor Theorem and Long Division

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