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Solving Mixture Problems

Mixture problems are word problems where items or quantities of different values are mixed together.

We recommend using a table to organize your information for mixture problems. Using a table allows you to think of one number at a time instead of trying to handle the whole mixture problem at once.

 

 

Replacing The Solution

Example:

A tank has a capacity of 10 gallons. When it is full, it contains 15% alcohol. How many gallons must be replaced by an 80% alcohol solution to give 10 gallons of 70% solution?

Solution:

Step 1: Set up a table for alcohol. The alcohol is replaced i.e. removed and added.

 

original

removed

added

result

concentration

       

amount

       

Step 2: Fill in the table with information given in the question.

A tank has a capacity of 10 gallons. When it is full, it contains 15% alcohol. How many gallons must be replaced by an 80% alcohol solution to give 10 gallons of 70% solution?

Change all the percent to decimals.

Let x = amount of alcohol solution replaced.

 

original

removed

added

result

concentration

0.15

0.15

0.8

0.7

amount

10

x

x

10

Step 3: Multiply down each column.

 

original

removed

added

result

concentration

0.15

0.15

0.8

0.7

amount

10

x

x

10

multiply

0.15 × 10

0.15 × x

0.8 × x

0.7 × 10

Step 4: Since the alcohol solution is replaced, we need to subtract and add.

original – removed + added = result
0.15 × 10 – 0.15 × x + 0.8 × x = 0.7 × 10
1.5 – 0.15x + 0.8x = 7

Isolate variable x
0.8x – 0.15x = 7 – 1.5
0.65x = 5.5
x=8.46

Answer: 8.46 gallons of alcohol solution needs to be replaced.

 

 

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Useful Links:
Mississippi Gulf Coast Community College - Mixture Problems
algebra.com - Mixture Problems
 
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