Solving Mixture Problems
Mixture problems are word problems where items or quantities of different values are mixed together.
We recommend using a table to organize your information for mixture problems. Using a table allows you to think of one number at a time instead of trying to handle the whole mixture problem at once.
Example:
A tank has a capacity of 10 gallons. When it is full, it contains 15% alcohol. How many gallons must be replaced by an 80% alcohol solution to give 10 gallons of 70% solution?
Solution:
Step 1: Set up a table for alcohol. The alcohol is replaced i.e. removed and added.
|
original |
removed |
added |
result |
concentration |
|
|
|
|
amount |
|
|
|
|
Step 2: Fill in the table with information given in the question.
A tank has a capacity of 10 gallons. When it is full, it contains 15% alcohol. How many gallons must be replaced by an 80% alcohol solution to give 10 gallons of 70% solution?
Change all the percent to decimals.
Let x = amount of alcohol solution replaced.
|
original |
removed |
added |
result |
concentration |
0.15 |
0.15 |
0.8 |
0.7 |
amount |
10 |
x |
x |
10 |
Step 3: Multiply down each column.
|
original |
removed |
added |
result |
concentration |
0.15 |
0.15 |
0.8 |
0.7 |
amount |
10 |
x |
x |
10 |
multiply |
0.15 × 10 |
0.15 × x |
0.8 × x |
0.7 × 10 |
Step 4: Since the alcohol solution is replaced, we need to subtract and add.
original – removed + added = result
0.15 × 10 – 0.15 × x + 0.8 × x = 0.7 × 10
1.5 – 0.15x + 0.8x = 7
Isolate variable x
0.8x – 0.15x = 7 – 1.5
0.65x = 5.5

Answer: 8.46 gallons of alcohol solution needs to be replaced.
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