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### A collection of Funny (or Flawed) Math Proofs

The above proof is incorrect because "Money is not the root of all evil". It is "The love of money that is the root of all evil" and of course "girls are not evil" (Proof by Majority Rule).

Both sides we will factorize. See?

Now each side contains a − b. [(a+b)(a − b) = b(a − b)]

We'll divide through by a

Minus b and olé

a + b = b. Oh whoopee! [a + b = b]

But since I said a = b

b + b = b you'll agree? [b + b = b]

So if b = 1

Then this sum I have done [1 + 1 = 1]

Proves that 2 = 1. Q.E.D.

Abbott & Costello prove that 7 times 13 = 28

Prove the manager wrong and get the job. Ma and Pa Kettle prove that 25 divided by 5 is 14

You can use the free Mathway calculator and problem solver below to practice Algebra or other math topics. Try the given examples, or type in your own problem and check your answer with the step-by-step explanations.

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**A Mathematical Proof that "Girls are Evil"**

1. “Girls require time and money”;

girls = time × money

2. “Time is money”:

time = money

3. So girls are money squared:

girls = money^{2}

4. ”Money is the root of all evil”:

money = \(\sqrt {evil} \)

5. So, girls are evil:

girls = \({\left( {\sqrt {evil} } \right)^2}\) = evil

The above proof is incorrect because "Money is not the root of all evil". It is "The love of money that is the root of all evil" and of course "girls are not evil" (Proof by Majority Rule).

**Prove that 2 = 1**

If a = b (so I say) [a = b]

And we multiply both sides by a

Then we'll see that a^{2} [a^{2} = ab]

When with ab compared

Are the same. Remove b^{2}. OK? [a^{2} − b^{2} = ab − b^{2}]

Both sides we will factorize. See?

Now each side contains a − b. [(a+b)(a − b) = b(a − b)]

We'll divide through by a

Minus b and olé

a + b = b. Oh whoopee! [a + b = b]

But since I said a = b

b + b = b you'll agree? [b + b = b]

So if b = 1

Then this sum I have done [1 + 1 = 1]

Proves that 2 = 1. Q.E.D.

Written by PeterW

(Just in case you're wondering - the above proof is incorrect because in step 5, we divided by (a - b) which is 0 since a = b)

Proof that $1 = 1 cent

$1 = 100 cents

= (10 cents)^{2}

= ($0.1)^{2}

= $0.01

= 1c

The above proof is incorrect because 100 cents = 10^{2} cents ≠ (10 cents)^{2}

A Proof that 0 = 1.

The above proof is incorrect because when we take the square root we must be careful to include both the positive and negative roots. There should then be two possible answers (one of which is to be rejected).Abbott & Costello prove that 7 times 13 = 28

Prove the manager wrong and get the job. Ma and Pa Kettle prove that 25 divided by 5 is 14

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You can use the free Mathway calculator and problem solver below to practice Algebra or other math topics. Try the given examples, or type in your own problem and check your answer with the step-by-step explanations.

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